Physics, asked by janetvarghese1298, 10 months ago

An orthogonal cutting operation is being carried out in which uncut thickness is 0.010 mm, cutting speed is 130 m/min, rake angle is $ 15^\circ $ and width of cut is 6 mm. It is observed that the chip thickness is 0.015 mm, the cutting force is 60 n and the thrust force is 25 n. The ratio of friction energy to total energy is

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Answered by gayathrisantho13
0

Answer:

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