Question

An otto cycle has net work done of 418.17 KJ/Kg and compression ratio of 8. The begning process of air is at at 17 celcius and 100 kpa. For this cycle calculate mean effective pressure

Answer 1

In the given otto cycle, to calculate the mean effective pressure:

Given Data:

• Net Work($W_{net}$) = 418.17 KJ/Kg.
• Compression ratio(r) = 8.
• Initial pressure($P_{i}$)= 100 kPa.
• Initial Temperature($T_{i}$) = 290 K.

Soln:

• initial volume($v_{1}$) which is equal to the maximum volume is given by

                              $v_{1}=v_{max}= R*T_{i} /P_{i}\\v_{1}= 0.2879*290/100\\v_{1}=0.834 m^3 /Kg$

• compression ratio(r) is given as

                              $r = v_{max}/v_{min}\\r = v_{1}/v_{2}\\v_{2}=v_{1}/r\\v_{2}=0.8329/8\\v_{2}=0.1043 m^3/Kg$

• Mean effective pressure is given by:

                              $M.E.P=W_{net}/(v_{1}-v_{2})\\M.E.P = 418.17/(.834-0.1043)\\M.E.P = 573.0711 kPa$  

Therefore the Mean effective power is 573.071 kPa

Answer 2

Answer:

574 hoga

ye shi Ans hao

option A