Question

An Otto engine has a clearance volume of 7%. It produces 300 kw power. What is the amount of heat rejected in kW?

Answer 1

Answer:

1.An Otto engine has clearance volume of 7%. Itproduces 300 kW power. What is the amount ofheat rejected in kW? Ans: Q= 152 kW 2.An air standard engine has a compression ratio of20 and a cut-off ratio of 5.

Explanation:

please follow kardo

Answer 2

Answer:

The amount of heat rejected in kW is  152 KW.

Explanation:

Given:

An Otto engine has a clearance volume (C)of 7%.=0.7

Power of otto cycle is 300kw

$r_{K}$ = compression ratio =$\frac{1+C}{C}$

                              = $\frac{1+0.7}{0.07}$

                              $= 15.286$

                         e = 1 – 1 / rkk-  1  

                      = 1 – [1 / 15.2860.4]                        ($w_{k} =p$=power of the otto

                                      = 0.664                                                  engine)

                                  $e=\frac{W_{K} }{Q_{A} }$                        ($Q_{A}$ is the amount of heat                                                                                                                                        

                                   $Q_{A}$ =$\frac{W_{K} }{e}$                        added to  otto engine)

                                 = 300 / 0.664

                                      = 452 KW                      ($Q_{R}$ is the amount of heat

                                  W = $Q_{A}$ – $Q_{R}$                    rejected from otto engine)

                                    300 = 452 –$Q_{R}$

                                    $Q_{R}$ = 152 KW

The amount of heat rejected in kW is  152 KW.

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