Question

An our contains 15 percentage iron. How much our will be required to get 18 kg of iron ?​

Answer 1

Answer:

100kg of an ore contains 15kg of iron. Let mass required to obtain 18kg of iron be 'x'. Then, 15/100 * x = 18kg ⇒ x = 1800kg/15 = 120kg. ∴ Mass required to obtain 18kg of iron is '120kg'.

Answer 2

Answer:

Hi friends

Step-by-step explanation:

100kg of an ore contains 15kg of iron. Let mass required to obtain 18kg of iron be 'x'. Then, 15/100 * x = 18kg ⇒ x = 1800kg/15 = 120kg. ∴ Mass required to obtain 18kg of iron is '120kg'.