Question

an oven takes 220 volt and 16 Ampere to operate if the current have to overcome to 12 Ampere what resistance should be connect in series​

Answer 1

Given,

Voltage (V) = 220 V

Current (I) = 12 A

∴ V = I*R

= 220 = 12R

= 18.34 Ω = R

A Resistance of 18.34 Ω is required for the current to be 12 A.

I hope this helps.

Answer 2

Answer:

The resistance connected in series will be 4.59Ω.

Explanation:

The resistance of the oven is given as,

$R=\frac{V}{I}$       (1)

Where,

R=resistance of the oven

V=voltage reading of the oven

I=current required for the oven to operate

From the question we have,

V=220 volts

I=16A

I'=12A

By substituting the value of "V" and "I" in equation (1) we get;

$R=\frac{220}{16}=13.75\Omega$       (2)

Let the resistance connected in series be "r". So, equation (1) can be written as,

$R+r=\frac{V}{I'}$       (3)

By substituting the values in equation (3) we get;

$13.75+r=\frac{220}{12}$

$13.75+r=18.34$

$r=18.34-13.75$

$r=4.59\Omega$

Hence, the resistance connected in series will be 4.59Ω.