an over covers 1/3 of its journey with speed v1 for rest journey moves with speed v2 for time t2 and with speed v3 for time t3 calculate it average speed
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Let the three equal distances be s each.
Now,
v=st⟹t=sv
The time intervals are, therefore,
t1=sv1
t2=sv2
t3=sv3
The average speed is given by,
⟨v⟩= Total DistanceTotal Time
⟨v⟩=s+s+ssv1+sv2+sv3
⟨v⟩=3ss(1v1+1v2+1v3
⟨v⟩=31v1+1v2+1v3
⟨v⟩=3v1v2v3v1v2+v2v3+v3v1
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