An overhead tank has two taps. One is working as inlet amd other as outlet. Id the tank can be filled in 3 hours by the inlet tap and it can be emptied by the outlet tap in 4 hours then find the time required to fill the tank, if both the taps are opened simultaneously.
Answers
Step-by-step explanation:
In pipes and water tank we will learn how to solve different types of problems. A water tank or a cistern is connected with two types of pipes to fill and empty it. The pipe which fills the tanks up is called the inlet. The pipe which empties it is called the outlet.
Suppose, if an inlet fills up the cistern in 5 hours, then in 1 hour it fills up 1/5 th part of it. We say that the work done by inlet in 1 hours is 1/5.
Similarly, if an outlet empties out the cistern in 4 hours, then in 1 hour it empties out 1/4 th part of the cistern. We say that the work done by the outlet in 1 hour is 1/4.
Now we will apply the concept of solving some real-life problems on pipes and a water tank or a cistern.
Answer:
Since, inlet tap fill the tank in 3 hours
therefore, Part of tank filled in 1 hour = 1/3 rd
And, outlet tap empty the tank in 4 hours
therefore, Part of tank emptied in 1 hour = 1/4 th
If both taps are open together,
Part of tank filled in 1 hour = 1/3 - 1/4
= 1/12 th
Hence,
Time required to fill the tank (if both taps are opened together) = 12 hours