An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ?
A) 2000
B) 3000
C) 2500
D) 3500
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An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ?
A) 2000
B) 3000
C) 2500
D) 3500
Let 's' be the number of small packets and 'b' the number of large packets sold on that day.
Therefore, s + b = 5000 ... eqn (1)
Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s.
Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b.
Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)
Or
150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150,
we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get
100b = 3,00,000
Or
b = 3000
➡️We know that s + b = 5000
So,
s = 5000 - b = 5000 - 3000 = 2000.
➡️Hence correct option is "A" 2000 s mall packets were sold.⬅️
A) 2000
B) 3000
C) 2500
D) 3500
Let 's' be the number of small packets and 'b' the number of large packets sold on that day.
Therefore, s + b = 5000 ... eqn (1)
Each small packet was sold for Rs.150.Therefore, 's' small packets would have fetched Rs.150s.
Each large packets was sold for Rs.250.Therefore, 'b' large packets would have fetched Rs.250b.
Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)
Or
150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150,
we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get
100b = 3,00,000
Or
b = 3000
➡️We know that s + b = 5000
So,
s = 5000 - b = 5000 - 3000 = 2000.
➡️Hence correct option is "A" 2000 s mall packets were sold.⬅️
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