Question

An owner of a motor garage bought two second hand cars for Rs.1,18,000 each. He sold one car at a loss of 15% and the other at a profit of 30%. Find his total loss or profit % in the whole transaction.​

Answer 1

Answer:

In the first case he gains 10%

∴ C. P. of the first car

=

110

100×9900

=Rs.9000

In the second case he loses 10%

∴ C. P. of the second car

=

90

100×9900

=Rs.11000

∴ Total cost of both cars

=9000+11000=Rs.20000

∴ Total S. P. of both cars

=2×9900=Rs.19800

∴ Total loss =20000−19800=Rs.200

∴ % of loss =

20000

200×100

=1%

here is answer ajkal study hard hehe

Answer 2

CP of car = Rs.150000

Repairing cost = Rs.10000

Total CP = 150000+10000 = Rs.160000

SP of car = Rs.200000

Profit = SP - CP

Profit = Rs. 200000-Rs.160000 = Rs.40000

Profit% = profit\CP × 100 CP

Profit

×100

Profit% = \frac{40000}{160000} \times 100

160000

40000

×100

Profit% = 25\%25%

Hence his gain % is 25%