An oxide metal m contains 40% by mass of 24 the empiricle formula is
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let the. 100g
then O is 40g
and (100-40)g =60g of metal
given mass of M/atomic mass : given mass of O/atomic mass
M. : O
60/24 :40/16
30/12:20/8
15/6 :10/4
5/2. :5/2
The ratio is 1:1 then formula is MO
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