Question

an oxide of a metal M contains 40% by mass of oxygen. Metal M has atomic mass of 24 the empirical formula of oxide is

Answer 1

let the. 100g
then O is 40g
and (100-40)g =60g of metal
given mass of M/atomic mass : given mass of O/atomic mass
M. : O
60/24 :40/16
30/12:20/8
15/6 :10/4
5/2. :5/2

The ratio is 1:1 then formula is MO
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Answer 2

$\bf \: Hey \: there$

since , we are having mass percent it is convenient to convert it into gram with respect to 100gm of the compound as the starting material thus in the 100 gm of sample of the above compound . 40g. of of o is present and rest is of other . that's 60 g of metal m

$\bf Tips \: and \: tricks \:$

→ Do remember to find Empirical formula we need numbers of moles and it's ratio , so you must do more practice in this sort of problems


$\boxed { \bf Formula \: for \: Mole = \frac{given \: mass }{atomic \: mass} }$

According to the question :-

• Number of mole of metal M = 60/24 = 2.5

• Number of mole of oxygen ( O )= 40/ 16 = 2.5

Hence the ratio of M and O is 1:1


$\boxed{ \bf \: Therefore \: the \: formula \: of \: compound \: is \: MO }$


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