Question

An oxide of element A was analysed and found to have mass ratio of A to oxygen equal to
7:3. Then formula of oxide can be : [Atomic mass of A = 56]
(A) A₂O₂
(B)A₂O₃
(C)AO
(D) A20​

Answer 1

Answer:

the answer is A2O3

Explanation:

the ratio is 7:3,so let's consider 70% of A and 30 %of B in the compound.

70/56=1.25

30/16=1.875.

now divide both with 1.25 ,you will get 1 &1.5

now multiply each by 2 you will get A=2&B=3