an oxide of iodine is equal to 127 contains 25.4 gram of iodine for 8 gram of oxygen its formula could be
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Answer:
I2O5
Explanation:
moles of l=given mass/molar mass
=25.4/127
=0.2 mole
mole of O=given mass/ molar mass
=8/16
=0.5
ratio = 2:5
thus the formula of compound is I2O5
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