An oxide of metal M has 40% by mass of oxygen. Metal M has atomic mass of 24. The empirical formula of the oxide is
1. M2O
2. M2O3
3. MO
4. M3O4
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Answer: The answer is M2O
Explanation: suppose you have 100g of metal oxide, then the mass of Oxygen will be 40g and the mass of metal will be 60 g.
For Oxygen :-
Given mass/molar mass =40 /32
=1.25moles
For Metal :-
Given mass/molar mass=60/24
=2.5moles
Now take the simple ratio
Oxygen:Metal =1.25:2.5
= 1:2
Therefore M20
riyaa07:
Thank you
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