An oxide of metal M has 40% by mass of oxygen. Metal M has atomic mass of 24. The empirical formula of the oxide is
1. M2O
2. M2O3
3. MO
4. M3O4
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Answer: The answer is M2O
Explanation: suppose you have 100g of metal oxide, then the mass of Oxygen will be 40g and the mass of metal will be 60 g.
For Oxygen :-
Given mass/molar mass =40 /32
=1.25moles
For Metal :-
Given mass/molar mass=60/24
=2.5moles
Now take the simple ratio
Oxygen:Metal =1.25:2.5
= 1:2
Therefore M20
riyaa07:
Thank you
But the correct ans is MO!!
Oh got it
Instead of molar mass we have to use atomic mass as the question says for finding empirical formula
So instead of dividing the given mass by 32 we have to divide it by 16 which is oxygen’s atomic mass
Sorry, my bad... I wrote 32 by mistake.. Thanks for correcting me on this.... I really appreciate it
It’s ok ur welcome! And also I appreciate u helping me. Thank ya!!!
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