Chemistry, asked by 261202, 1 year ago

an oxide of metal M has 47% by mass of oxygen. Metal M has atomic mass of 24. the empirical formula of the oxide is

Answers

Answered by 0BRAINLY01
16
HEYA MATE,

HERE IS UR ANSWER.

Thanks for asking this question.

The formulae of the oxide is :

M x O y

Let X be moles of M and y be moles of Oxygen.

Mass of oxygen is 0.47g

Mass of M is 0.53g

Moles of M = 0.53 / 24 = 0.02

Moles of Oxygen = 0.47 / 16 = 0.03

Mole ratio :

M : O = 0.02 : 0.03

= 2:3

The empirical formula of the oxide is thus :

M3O4

I HOPE IT HELPS U.

261202: answrr is M3O4
261202: ratio is 2:3 so how formula is m3o4
0BRAINLY01: M2O3
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