an oxide of metal M has 47% by mass of oxygen. Metal M has atomic mass of 24. the empirical formula of the oxide is
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HEYA MATE,
HERE IS UR ANSWER.
Thanks for asking this question.
The formulae of the oxide is :
M x O y
Let X be moles of M and y be moles of Oxygen.
Mass of oxygen is 0.47g
Mass of M is 0.53g
Moles of M = 0.53 / 24 = 0.02
Moles of Oxygen = 0.47 / 16 = 0.03
Mole ratio :
M : O = 0.02 : 0.03
= 2:3
The empirical formula of the oxide is thus :
M3O4
I HOPE IT HELPS U.
HERE IS UR ANSWER.
Thanks for asking this question.
The formulae of the oxide is :
M x O y
Let X be moles of M and y be moles of Oxygen.
Mass of oxygen is 0.47g
Mass of M is 0.53g
Moles of M = 0.53 / 24 = 0.02
Moles of Oxygen = 0.47 / 16 = 0.03
Mole ratio :
M : O = 0.02 : 0.03
= 2:3
The empirical formula of the oxide is thus :
M3O4
I HOPE IT HELPS U.
261202:
answrr is M3O4
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