an oxide of nitrogen consits of 63.6% of nitrogen. what is the empirical formula of the compound? what is the name of the compound?
Answers
N and O are the two Compounds
N=18
O=16
There atomic mass
Now
Percentage %
N=63.6
O=34.3
So
Simplest Ratio
N=63.6/18=2
O=34.3/16=1
Now
Empirical formulae =
2NO
So formula is N2O
Hope it helps you
The empirical formula of the compound is N₂O
The name of the compound is Nitrous oxide
Given:
Oxide of nitrogen
consists of 63.6% nitrogen
To find:
To find the empirical formula and name of the compound
Solution:
To get the empirical formula of the compound we must know each atom's atomic mass and the percentage present in the compound.
The two atoms present are Nitrogen and Oxygen
Atomic masses of the given atoms are,
N = 14
O = 16
Percentage present in the compound,
N = 63.6% (given)
O = 100 - 63.6 = 36.4%
We can now get the simplest ratio by the formula ⇒
percentage present in compound/ atomic mass
N = 63.6 / 14 = 4.542 -----> (1)
O = 36.4 / 16 = 2.275 -----> (2)
The empirical formula can have only whole number ratios
Diving (1) and (2) by 2.75
N = 4.542/2.275 = 1.99 ≈ 2
O = 2.75/2.75 = 1
Therefore,
We have 2 moles of N + 1 mole of O => formula = N₂O
Hence,
The empirical formula of the given compound is N₂O
the name of this compound is nitrous oxide.
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