Question

an oxide of nitrogen consits of 63.6% of nitrogen. what is the empirical formula of the compound? what is the name of the compound?

Answer 1

N and O are the two Compounds

N=18

O=16

There atomic mass

Now

Percentage %

N=63.6

O=34.3

So

Simplest Ratio

N=63.6/18=2

O=34.3/16=1

Now

Empirical formulae =

2NO

So formula is N2O

Hope it helps you

Answer 2

The empirical formula of the compound is N₂O

The name of the compound is Nitrous oxide

Given:

Oxide of nitrogen

consists of 63.6% nitrogen

To find:

To find the empirical formula and name of the compound

Solution:

To get the empirical formula of the compound we must know each atom's atomic mass and the percentage present in the compound.

The two atoms present are Nitrogen and Oxygen

Atomic masses of the given atoms are,

N = 14

O = 16

Percentage present in the compound,

N = 63.6% (given)

O = 100 - 63.6 = 36.4%

We can now get the simplest ratio by the formula ⇒

percentage present in compound/ atomic mass

N = 63.6 / 14 = 4.542  -----> (1)

O = 36.4 / 16 = 2.275  -----> (2)

The empirical formula can have only whole number ratios

Diving (1) and (2) by 2.75

N = 4.542/2.275 = 1.99 ≈ 2

O = 2.75/2.75 = 1

Therefore,

We have 2 moles of N + 1 mole of O => formula = N₂O

Hence,

The empirical formula of the given compound is N₂O

the name of this compound is nitrous oxide.

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