Question

an oxide of nitrogen containing 30. 43% and the molecular mass of the compound is equal to 92 a m u calculate the molecular formula of the compound
pls answer and explain it properly​

Answer 1

Answer:

N   = 30.43            14     2.17

O = 69.57             16       4.34

Emphirical formula = NO2

Molecular formula = N2O4

Molarity = n/v = 1/0.018 = 1000/18

              = 55.55m

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