an oxide of Nitrogen containing 30.43% of Nitrogen. the molecular mass of compound is 92. calculate the molarity of the solution.
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Are you sure its molarity and not molality?
ya sure
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i think the molarity is incorrect ask ur teacher
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Answer:
N = 30.43 14 2.17
O = 69.57 16 4.34
Emphirical formula = NO2
Molecular formula = N2O4
Molarity = n/v = 1/0.018 = 1000/18
= 55.55m
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