Question

an oxide of nitrogen contains of its own volume of nitrogen and it's vapour density is 38. Determine its molecular formula.​

Answer 1

Answer:

N20

Explanation:

We all know Avogadro’s law, that under the same conditions of temperature and pressure, equal volumes of different gases contain an equal number of molecules.

It is mentioned in question that oxide contains its own volume of nitrogen i.e

1 molecule of oxide= 1 molecule of nitrogen.

So with this we get empirical formula (N2O)

molecular weight = 2 × 38 = 76

we can write that molecular weight of N2Ox is 76

so 28 + 16x = 76

16x = 48

x = 3

so the molecular formula comes out to be N2O3.