Question

an oxide of Nitrogen has a molecular weight of 46 total number of electrons in one molecule of the compound is​

Answer 1

now let us assume that in that oxide *per molecule* there are 'x' atoms of nitrogen and 'y' atoms of oxygen then molecular weigh is given by :

X×14 + Y×16 [ since atomic weigh of nitrogen is 14 and that of oxygen is 16]

now according to question molecualr weigh is 46 =>

14x +16y = 46

according to hit and trial method,

X =1 and Y=2

=> chemical formulae of compound was NO2

=> total number of electrons in that compound is :

7(from nitrogen) + 2×8(from two atom of oxygen)

=7 + 16

=23.

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