An oxide of sulphur contain 66.67%sulphur what is its empirical formula.
ONLY DOO IT BY TABLE METHOD OF EMPIRICAL FORMULA )
ANSER IS S202
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Answer:
Divide each mass percentage by ATOMIC mass of each element:
S = 50/32 = 1.5625
O = 50/16 = 3.125
Divide through by smaller:
S = 1.5625/1.5625 = 1
O = 3.125/1.5625 = 2
Empirical formula = SO2
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