Question

An oxide of sulphur contains 50 of sulphur in it its empirical formula is

Answer 1

Divide each mass percentage by ATOMIC mass of each element:

S = 50/32 = 1.5625

O = 50/16 = 3.125

Divide through by smaller:

S = 1.5625/1.5625 = 1

O = 3.125/1.5625 = 2

Empirical formula = SO2

Answer 2

Answer:

Hi there,

given....

☆ sulphur oxide: The atom are S,O

☆ The % of S is 50%

☆ The % of O is 50%

☆ Atomic mass S is 32

☆ Atomic mass O is 16