Chemistry, asked by Bunny1159, 1 year ago

An oxide of sulphur contains 50 of sulphur in it its empirical formula is

Answers

Answered by Anonymous
77

Divide each mass percentage by ATOMIC mass of each element:

S = 50/32 = 1.5625

O = 50/16 = 3.125

Divide through by smaller:

S = 1.5625/1.5625 = 1

O = 3.125/1.5625 = 2

Empirical formula = SO2

Answered by ratanprakashhappy
8

Answer:

Hi there,

given....

☆ sulphur oxide: The atom are S,O

☆ The % of S is 50%

☆ The % of O is 50%

☆ Atomic mass S is 32

☆ Atomic mass O is 16

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