An oxide of sulphur contains 50 of sulphur in it its empirical formula is
Answers
Answered by
77
Divide each mass percentage by ATOMIC mass of each element:
S = 50/32 = 1.5625
O = 50/16 = 3.125
Divide through by smaller:
S = 1.5625/1.5625 = 1
O = 3.125/1.5625 = 2
Empirical formula = SO2
Answered by
8
Answer:
Hi there,
given....
☆ sulphur oxide: The atom are S,O
☆ The % of S is 50%
☆ The % of O is 50%
☆ Atomic mass S is 32
☆ Atomic mass O is 16
Attachments:
Similar questions