An oxide of uranium contains 84.8% of uranium. The empirical formula of the oxide is ? ( atomic mass of U = 238 , O = 16)
Answers
please make it as brainliest.
Answer:
The empirical formula for the compound containing uranium and fluorine is
UF
6
.
Explanation:
The empirical formula of a compound represents the lowest whole number ratio of elements in the compound. This ratio is represented by subscripts in the formula. In order to determine the empirical formula, we first must determine the number of moles of each element and then determine the mole ratio of each element. The mole ratio will give us the subscripts for the empirical formula.
Since the percentages of each element add up to 100, we can assume a 100 g sample of the compound and convert the percentages to grams.
Masses
U
:
67.6
%
⇒
67.6 g
F
:
32.4
%
⇒
32.4 g
Molar Masses
U
:
238.02891 g/mol
F
:
18.99840316 g/mol
Moles
Divide the mass of each element by its molar mass (atomic weight on the periodic table in g/mol).
U
:
67.6
g U
×
1
mol U
238.02891
g U
=
0.284 mol U
F
:
32.4
g F
×
1
mol F
18.99840316
g F
=
1.71 mol F
Mole Ratios
Divide the number of moles of each element by the lowest number of moles.
U
:
0.284
mol
0.284
mol
=
1.00
F
:
1.71
mol
0.284
mol
=
6.02
≈
6
The empirical formula for this compound is
UF
6.
HOPE THAT IT WILL HELP YOU MATE.