Question

An oxygen sample has a volume of 4.50 L at 27°C and 800.0 torr. How many moles oxygen does it contain?​

Answer 1

Explanation:

The volume of the oxygen gas is V= 4.50 L

The temperature of the oxygen gas is T=27°C = 300K

The pressure of the oxygen gas is P= 800.0 torr(1 atm/760 torr) = 1.05 atm

The expression for the number of molecules of oxygen is,

N = number of moles of oxygen × avogadro's number

= PV/RT × 6.023 × 10^23

Substituting the known values in the above expression.

N = (1.05 atm) (4.50 L) (6.023 × 10^23) /

(0.08205 L atm /mole K) (300 K)

N ~ 1.16 × 10^23 molecules

Thus, it contains 1.16 × 10^23 molecules of oxygen

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