Question

. An -particle having kinetic energy 4.0 MeV is projected towards a nucleus (Z=50). Select the correct information(s)
(D) two quantum mechanical spin states
regarding the a-particle : [1 MeV = 106 eV]
(A) Its distance of closest approach towards the nucleus is 3.6x 10-14 m.
(B) Its potential energy at a distance of 9.0 x 10-14 m from the nucleus is 1.6 MeV.
(C) Its kinetic energy at a distance of 4.5 x 10-14 m from the nucleus is 0.8 MeV.
(D) At a moment, the distance between a-particle and the nucleus becomes 2.0 x 10-16 m​

Answer 1

Answer:

C

Explanation:

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