Physics, asked by radha8288, 7 months ago

An particle moves in a circular path with a constant speed of 10m/s.Find its average acceleration when it cross two radially perpendicular location time of particle is 8s.

Answers

Answered by liyutsa80

1

Answer:

Acceleration = v-u/t. Here u = 0

10-0/8 = 10/8 = 5/4

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