An quadrilateral triangle has sides of length 25 CM if the side of triangle is increased by 30% then find what fraction of the perimeter of the new triangle is perimeter of previous triangle
Answers
Answer:
10/13
Step-by-step explanation:
Side of the *equilateral triangle is 25 cm.
Perimeter of equilateral triangle = 3a
= 3(25)
= 75 cm
If the each side is increased by 30%,
new side = 25 + (30% of 25)
= 25 + 0.3*25
= 32.5
∴ New perimeter = 3(32.5)
= 97.5
Required fraction = 75/97.5
= 750/975
= 10/13
Hence the previous perimeter is 10/13 th of the new perimeter.
Answer:
- Previous perimeter of triangle is 10/13 th of perimeter of new triangle.
Explanation:
It is given that, an equilateral triangle has side of length 25 cm, each side of triangle is increased by 30%.
We have to find that what fraction of the perimeter of the new triangle is perimeter of previous triangle.
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Firstly let's find the perimeter of given triangle. As we know that given triangle is equilateral triangle. So, its perimeter is given by;
- Perimeter = 3 × side
Putting all values we get,
➻ Perimeter = 3 × 25
➻ Perimeter = 75 cm
- Hence, perimeter of triangle is 75 cm.
Now, we know that each side is increases by 30% so the new side will be;
➻ New side = 25 + (30% of 25)
➻ New side =25 + (30/100 × 25)
➻ New side = 25 + (30/4 × 1)
➻ New side = 25 + 7.5
➻ New side = 32.5 cm
- Hence, new side of triangle is 32.5 cm.
Now, we have new side formed after increasing its side by 30% so now let's find its new perimeter by using same formula;
- Perimeter = 3 × side
Putting all values we get,
➻ New perimeter = 3 × 32.5
➻ New perimeter = 97.5 cm
- Hence, new perimeter of triangle is 97.5 cm.
Now, required fraction will be;
➻ Required fraction = (Previous perimeter)/(New perimeter)
➻ Required fraction = 75/97.5
➻ Required fraction = 10/13
- Hence, Previous perimeter of triangle is 10/13 th of perimeter of new triangle.
Know more:
- Perimeter of any figure is calculated by sum of its all sides
- Perimeter of square = 4 × side
- Perimeter of equilateral ∆ = 3 × side
- Perimeter of rhombus = 4 × side
- Perimeter of circle = 2πr
- Perimeter of rectangle = 2(l + b)