An RC series circuit draws 0.5A current at 50 Hz. Voltage drop across
capacitance is 150V and voltage drop across resistance is 80V. Compute
(i) The applied voltage
(ii) impedance,
(iii) Value of resistance
(iv) Value of capacitance connected
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A resistor of 100Ω, a pure inductance coil of L = 0.5 H and capacitor are in series in a circuit containing an a.c sources of 200 V, 50 Hz. In the circuit, current is added is ahead of the voltage by 30
0
.Find the value of the capacitance
Medium
Solution
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Correct option is A)
In the circuits
Inductive Reactance X
2
=2πvL=2π(50)×(0.5)=50πΩ
Let capacitance be C so, x
c
=
2πvc
1
=
100πc
1
an current leads voltage (circuit is more capacitive) by 30
o
,=ϕ
tanϕ=
R
X
C
−X
L
⇒tan30
o
=
100
100πc
1
B−50π
that gives C=1.46F
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