An rerefrigerator having a power rating of 350 watts operated for 10 hours a day.calculate the electrical energy to operater it for a month 30days .the rate of electric energy is₹3.4 per/kmh.
Answers
Answer:
The answer if followed by:
it is giving that a refrigerator having a power rating of 350 watts operated for 10 hours a day and we have to find the the watts operated for 30 days and then it is said to find the rate of electric energy is 3.4 per/kmh
Explanation:
Now first we have to find the the power rating of 30 days if it is operated for 10 hours in a day and it's watts is 350
So we know that ELECTRIC COMSIME= power×time= 350÷1000= 0.35
now in 10 hours = 0.35×10=3.50 kwh
in 30 days = 105 kwh
Now it is given that if 3.4 rupees per/kwh.
so for 105 kwh= 105×3.4= 357 is the correct answer.
Answer:
energy consumed = 3.5 kwh
cost = rs. 357
Explanation:
energy consumed = power x time
= 350 W x 10 hrs
= 3500 Wh = 3.5 kWh
cost in 30 days = 3.5 kWh x 30 days x rs.3.4
= 357 rs.