Question

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Example 8: A 25 m long ladder exactly
reaches a window 24 m high from the
ground when placed against a wall at a
distance x m. Find the distance between the
foot of the ladder and the wall.
Solution: Let AB be the ladder and BC be
the wall.
Then, AB = 25 m and BC = 24 m
Let the distance between the
foot of ladder and wall be x m.
AACB is a right-angled triangle
at C.
By Pythagoras' property, we
have
AC? + BC = AB
r+242 = 252
B
24 m
25 m
Properties of Triang
C xm A
n​

Answer 1

Answer:

S

Example 8: A 25 m long ladder exactly

reaches a window 24 m high from the

ground when placed against a wall at a

distance x m. Find the distance between the

foot of the ladder and the wall.

Solution: Let AB be the ladder and BC be

the wall.

Then, AB = 25 m and BC = 24 m

Let the distance between the

foot of ladder and wall be x m.

AACB is a right-angled triangle

at C.

By Pythagoras' property, we

have

AC? + BC = AB

r+242 = 252

B

24 m

25 m

Properties of Triang

C xm A

n

Step-by-step explanation:

S

Example 8: A 25 m long ladder exactly

reaches a window 24 m high from the

ground when placed against a wall at a

distance x m. Find the distance between the

foot of the ladder and the wall.

Solution: Let AB be the ladder and BC be

the wall.ns. d d i am fine 7

Then, AB = 25 m and BC = 24 m

Let the distance between the

foot of ladder and wall be x m.

AACB is a right-angled triangle

at C.

By Pythagoras' property, we

have

AC? + BC = AB

r+242 = 252

B

24 m

25 m

Properties of Triang

C xm A

n