Question

An sphere of mass 40kg is attracted by a second sphere of mass 15kg when their centers are 0.2 m apart with force of 9.8×10^-7.calculate value of G​

Answer 1

Answer:

As F = GmM / r²

9.8 x 10 ⁻⁷ = G x 15 x 40 / (0.2)²

9.8 x 10 ⁻⁷ = G x 600/ 0.04

9.8(0.04) x 10⁻⁷ = 600G

3.92 x 10⁻⁶ = 600G

G = 6.53 x 10⁻¹¹

Answer 2

Answer:

9.8×10^-7=m1m2 G/r^2=

G×40×15/4/100= G×60000/4=15000G

therefore G=9.8×10-7/1.5×10^4=6.5333..×10^-11