Question

An ultrasonic transducer used for medical diagnosis oscillates at a frequency of 6.7 MHz = 6.7 x 10^6Hz, how much time does each oscillation take, and what is the angular frequency of the oscillation

Answer 1

Given : Frequency $\mathfrax{f}$ = $6.7 \times 10^{6} \: Hz$

To Find : Times of Oscillation {T} ; Angular frequency $\omega$

Solution :

T = $\dfrac{1}{f}$

T = $\dfrac{1}{6.7\times10^{6}}$

T = $1.5 \times 10^{-6}$

T = $1.5 \:\mu s$

$\omega \: = \: 2πf$

$\omega \: = \: 2 \times 3.17 \times 6.7\times 10^{6}$

$\omega \: = \: 4.2\times 10^{7} \: rad/sec$

Answer :

Times of Oscillation {T} = $1.5 \:\mu s$

Angular frequency $\omega \: = \: 4.2\times 10^{7} \: rad/sec$

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Answer 2

Frequency is the number of occurrences of a repeating event per unit of time. It is also occasionally referred to as temporal frequency to emphasize the contrast to spatial frequency, and ordinary frequency to emphasize the contrast to angular frequency.

In physics, the wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.

find: times of oscillation{T}; Angular frequency $\omega$

Solution

$T=\frac{1}{f}$

$T=\frac{1}{6.7\times 10^6}$

$T=1.5\times 10^{-6}$

$T=1.5\mu s$

$\omega =2f$

$\omega =2\times 3.17\times 6.7 \times 10^6$

$\omega =4.3\times 10^7 rad\sec$

Answer

Tims of oscillation (T)=1.5\mu s

Angular frequency \omega = 4.2\times 10^7 rad/sec

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