Question

an umbrella is made by stiching 10 triangular pieces of cloth of two different colours each piece measuring 20 CM, 50cm and 50cm how much cloth of each colour is required for the umbrella​

Answer 1

Answer:

First you have to find the semi perimeter of a single triangle which is sixty...Then find the the area using heron's formula and then the result will be as shown

Answer 2

Given

✭ There is a umbrella made up of 10 triangular pieces of length 20 cm, 50 cm & 50 cm

✭ Amit is gonna make 20 such umbrellas

$\displaystyle\large \underline \ \underline{\sf\orange{To \ Find}}$

◈ Length of the cloth required?

$\displaystyle\large\underline{\sf\gray{Solution}} </p><p>$

So here we may find the area of each triangular pieces, then multiply it with the number of triangles and then with the total number of umbrellas!!

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$\underline{\bigstar\:\textsf{According to the given Question :}} </p><p>★$

So we shall first find the semi perimeter, that is,

$.</p><p></p><p>›› \displaystyle\sf Semi \ Perimeter = \dfrac{20+50+50}{2}$

$›› \displaystyle\sf Semi \ Perimeter = \dfrac{120}{2}</p><p>$

$›› \displaystyle\sf \orange{Semi \ Perimeter = 60 \ cm}</p><p>$

So then we shall find the are with the help of the Heron's formula, that is,

$\displaystyle\underline{\boxed{\sf Area = \sqrt{s(s-a)(s-b)(s-c)}}}$

s = 60

a = 20

b = 50

c = 50

Substituting the values,

$➝ \displaystyle\sf Area = \sqrt{s(s-a)(s-b)(s-c)} \\ </p><p></p><p> </p><p> </p><p></p><p>➝ \displaystyle\sf \sqrt{60(60-20)(60-50)(60-50)} \\ </p><p></p><p> </p><p> </p><p></p><p>➝ \displaystyle\sf \sqrt{60\times 40\times10\times 10} \\ </p><p> </p><p> </p><p></p><p>➝ \displaystyle\sf \sqrt{240000} </p><p> </p><p> </p><p></p><p>➝ \displaystyle\sf \red{489.9 \ cm^2}$

Now for 1 umbrella we use 10 such pieces,so

$»» \displaystyle\sf 489.9 \times 10489.9×10 \\ </p><p></p><p>»» \displaystyle\sf \orange{Per \ Umbrella = 4899 \ cm^2}</p><p></p><p>$

So then for 20 such umbrellas,

$➳ \displaystyle\sf 4899\times 204899×20 \\ </p><p></p><p>➳ \displaystyle\sf \pink{97980 \ cm^2}</p><p></p><p>$

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