Question

An unbaised coin is tossed 10 times . Find the probability of getting at least one head

Answer 1

.Answer:

Step-by-step explanation:

the coin have two sides so, head=frequeny/total sides . the probabilty is =1/2

Answer 2

getting at least one head means minimum we can get 1 head or more than one head.
so no of outcome is 10.
n(s)=10
let a be atleast one head
then p(a)=n(a)/n(s)
if a=1 then propabibility =0.1
if a=2 then propabibility =0.2
if a=3 then propabibility =0.3
if a=4 then propabibility =0.4
if a=5 then propabibility =0.5
if a=6 then propabibility =0.6
if a=7 then propabibility =0.7
if a=8 then propabibility =0.8
if a=9 then propabibility =0.9
if a=10 then propabibility =1