An unbaised die is thrown . what is probality of getting (a) an even number (b) a multiply of 3 (c) a number less than 5 (d) a number between 3 and 6
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when a dice is thrown we get the following out comes
S = { 1,2,3,4,5,6}
n(S) = 6
probability of getting 3 is 1/6 [as there is only one 3]
probability of getting 4 is 1/6 [ there is only one 4]
Using addition theorem of of probability ,
probability of getting 3 or 4 is 1/6 + 1/6 = 2/6 = 1/3
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when a dice is thrown we get the following out comes
S = { 1,2,3,4,5,6}
n(S) = 6
probability of getting 3 is 1/6 [as there is only one 3]
probability of getting 4 is 1/6 [ there is only one 4]
Using addition theorem of of probability ,
probability of getting 3 or 4 is 1/6 + 1/6 = 2/6 = 1/3
hope it helps please mark me add brainliest
Answered by
1
Sample space (1,2,3,4,5,6)
A)= 3/6=1/2
b)=2/6=1/3
c)=4/6=2/3
d)=2/6=1/3
hope well!!
A)= 3/6=1/2
b)=2/6=1/3
c)=4/6=2/3
d)=2/6=1/3
hope well!!
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