Question

An unbalanced force of 48 N is applied to an object with a mask of 12 kg what is its acceleration rate?

Answer 1

Given :-

Force = F = 48 N

Mass of object = m = 12 Kg

As per the expression of Force, we can proceed that.

F = ma

48 = 12a

a = 4 ms-²

Answer 2

Answer:

Appropriate Question :-

• An unbalanced force of 48 N is applied to an object with a mass of 12 kg. What is the acceleration rate?

Given :-

• An unbalanced force of 48 N is applied to an object with a mass of 12 kg.

To Find :-

• What is the acceleration rate.

Formula Used :-

$\clubsuit$ Newton's Second Law :

$\longmapsto \sf\boxed{\bold{\pink{F =\: ma}}}$

where,

• F = Force
• m = Mass
• a = Acceleration

Solution :-

Given :

• Force (F) = 48 N
• Mass (m) = 12 kg

According to the question by using the formula we get,

$\dashrightarrow \rm\bold{\purple{F =\: ma}}$

$\bigstar \: \: \rm\bold{a =\: \dfrac{F}{m}}\: \: \bigstar$

Then,

$\implies \sf a =\: \dfrac{\cancel{48}}{\cancel{12}}$

$\implies \sf a =\: \dfrac{\cancel{24}}{\cancel{6}}$

$\implies \sf a =\: \dfrac{\cancel{12}}{\cancel{3}}$

$\implies \sf a =\: \dfrac{4}{1}$

$\implies \sf\bold{\red{a =\: 4\: m/s^2}}$

$\therefore$ The acceleration rate is 4 m/s².

$\rule{150}{2}$

EXTRA INFORMATION :-

$\bullet$ Rate of change of speed is called velocity.

$\diamondsuit$ Momentum :

• The amount of motion in the body is denoted by the quantity is called momentum.

$\diamondsuit$ Newton's First Law of Motion :

• Body maintain its state of rest or uniform motion along straight line, until and unless an unbalanced force acting on it.

$\diamondsuit$ Newton's Second Law of Motion :

• The rate of change of momentum is proportional to the applied unbalanced force.

$\diamondsuit$ Newton's Third Law of Motion :

• When one object exerts a force on another object, the second object instántaneously exerts a force, equal and opposite, back on the first.