Question

An unbiased cubic die is thrown.What is the probabiltiy of getting a multiple of 3 or 4?

A) 1/12 B) 1/9 C) 3/4 D) 1/2

Answer 1

Step-by-step explanation:

In a single throw of a die we can get any one of the six numbers { 1, 2, 3 , 4 , 5, 6 } marked on its six faces.

Therefore, the total number of elementary events associated with the random experiment of throwing a die is 6.

Let A denote the event "Getting multiple of 3 or 4"

Clearly, A occurs when we get either 3 or 4 as an outcome.

Favourable number of elementary events = 3

Hence,

P(A) = 3/6 = 1/2

Shortcut method,

S = { 1,2,3,4,5,6}

n(S) = 6

E = ( 4 , 3 , 6 )

n(E) = 3

P = n(E) / n(S) = 3/6 = 1/2