an unbiased dice is thrown four times find the probability of vetting 1 at least once
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Explanation:
Probability 1 does not appear is 5/6 for the each one 5/6
Probability 1 does not appear at all = 5/6 × 5/6 × 5/6 = 125/216
Probability 1 apears at least once = 1 - 125/216
=( 216- 125)/216 = 91/216
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