An unbiased die is thrown.Find the probability of getting an even number or a multiple of 3
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p(3)=(3,6)
p(even)=(2,46)
now p(3)=2/6
p(even)=3/6
p(3 n even)=1/6
p(3Ueven)=p(3)+p(even)-p(3 n even)
=2/6 +3/6 -1/6
=5/6 -1/6
=4/6
=2/3 is answer obtained
p(even)=(2,46)
now p(3)=2/6
p(even)=3/6
p(3 n even)=1/6
p(3Ueven)=p(3)+p(even)-p(3 n even)
=2/6 +3/6 -1/6
=5/6 -1/6
=4/6
=2/3 is answer obtained
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