An unbiased die is thrown once what is the probability of getting no greater than 4
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Answered by
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Heya!
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◾When an unbiased die is thrown ,
➡Total Outcomes = 6 [ 1 , 2 , 3 , 4 , 5 , 6 ]
➡Favourable Outcomes = [ 5 , 6 ]
✔Probability of an Event ( E ) = Favourable Outcomes/ Total Outcomes
✔P ( Getting a number greater than 4 ) = 2 / 6
= P ( E ) = 1 /3
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◾When an unbiased die is thrown ,
➡Total Outcomes = 6 [ 1 , 2 , 3 , 4 , 5 , 6 ]
➡Favourable Outcomes = [ 5 , 6 ]
✔Probability of an Event ( E ) = Favourable Outcomes/ Total Outcomes
✔P ( Getting a number greater than 4 ) = 2 / 6
= P ( E ) = 1 /3
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DevilDoll12:
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Answered by
1
Answer: 1/3
Step-by-step explanation:
Total number of outcomes = 6 {1,2,3,4,5,6}
(i) Number of times a number more than 4 would occur = 2 {5,6}
P(E) = 2/6 = 1/3
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