Question

An unbiased die is thrown. What is the probability of getting an even number or a multiple of 3 ?

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Answer 1

Answer:

Solution

In a single throw of an unbiased dice, you can get any one of the outcomes: 1, 2, 3, 4, 5, or 6.

So, exhaustive number of cases = 6.

(i) An even number is obtained if you obtain any one of 2, 4, 6 as an outcome.

So, favourable number of cases = 3.

Thus, required probability = 3/6 = 1/2

(ii) A multiple of 3 is obtained if you obtain any one of 3, 6 as an outcome.

So, favourable number of cases = 2

Thus, required probability = 2/6 = 1/3

(iii) An even number or a multiple of 3 is obtained in any of the following outcomes 2, 3, 4, 6.

So, favourable number of cases = 4.

Thus, required probability = 4/6 = 2/3

(iv) An even number and a multiple of 3 is obtained if you get 6 as an outcome.

So, favourable number of cases = 1.

Thus, required probability = 1/6

Step-by-step explanation:

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Answer 2

Probability

= No. ofFavourable outcomes/Total no. of outcomes

A die has 6 sides, therefore it has 6 numbers(1 to 6)

Favourable outcomes = 3,6 (Multiples of 3 are 3 and 6). Therefore, no. of favourable outcomes = 2

Total no. of outcomes = 6. (A die has six sides)

Therefore,

Probability = 2/6 = 1/3