an unbiased die is thrown. what is the probability of getting a). a number less than 5 divisible by 2. b). a number greater than 2 divisible by 3. c). an even number or a multiple of 3. d). an even number and a multiple of 3 e). a number 3 or 4. f). a number between 3 and 6
Answers
Answer:
a. 1/3
b. 1/3
c. 1/2
d. 1/6
e. 1/3
f. 1/3
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Given:
Given that an unbiased die is thrown.
To Find:
We have to find out the following.
a) A number that is divisible by two and is less than five.
b). A number greater than 2 is divisible by 3.
c). An even number or a multiple of 3.
d). An even number and a multiple of 3.
e). A number either 3 or 4.
f). A number between 3 and 6.
Solution:
The numbers obtained in a single throw of dice = 1, 2, 3, 4, 5 or 6.
∴, Total number of outcomes = 6.
a). The numbers that are divisible by two and are less than five = 1, 2, 3, 4.
Favorable number of outcomes = 4.
P (numbers that are divisible by two and are less than five) =
b). The numbers that are greater than 2 and is divisible by 3 = 3, 6.
Favorable number of outcomes = 2.
P (numbers that are greater than 2 and is divisible by 3) =
c). The numbers that are even or a multiple of 3 = 2, 3, 4, 6.
Favorable number of outcomes = 4.
P (numbers that are even or a multiple of 3) =
d). The numbers that are even and a multiple of 3 = 6.
Favorable number of outcomes = 1.
P (numbers that are even and a multiple of 3) =
e). The numbers that is either 3 or 4 = 3, 4.
Favorable number of outcomes = 2.
P (numbers that is either 3 or 4) =
f). The numbers between 3 and 6 = 4, 5.
Favorable number of outcomes = 2.
P (numbers between 3 and 6) =
Hence, the probability of the given situations, a, b, c, d, e, and f are , respectively.
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