Question

An unbiased die is thrown. What is the probability of getting:
(i) an even number or a multiple of 3
(ii) an even number and a multiple of 3
(iii) a number of 3 or 4​

Answer 1

Answer:

Step-by-step explanation

Random experiment - a dice is thrown

Let S be the sample space

S = {1,2,3,4,5,6}

n(S)= 6

Let A be the event of getting an even number or a multiple of 3

A ={ 2,3,4,6 }

n(A) = 4

P(A)=n(A) ÷ n(S)

= 4÷6

=2/3

Let B be the event of getting an even number and a multiple of 3

B = { 6 }

n(B) = 1

P(B) = n(B) ÷ n(S)

= 1/6

Let C be the event of getting a 3 or 4

C = {3,4}

n(C) = 2

P(C) = n(C) ÷ n(S)

= 2÷6

=1/3

Answer 2

i) multiple of three are 3, 6

p (e) = 2/6 = 1/3

even no : 2, 4

p(e)= 2/6= 1/3

ii) even and multiple = 0

impossible event cause even nos are not multiples of three

iii) 3or 4 = 1/6