Question

an unbiased die is thrown what is the probability of getting an even number and multiple of 3 2nd a number between 3 and 6​

Answer 1

Answer:

In a single throw of an unbiased dice, you can get any one of the outcomes: 1, 2, 3, 4, 5, or 6.

So, exhaustive number of cases = 6.

(i) An even number is obtained if you obtain any one of 2, 4, 6 as an outcome.

So, favourable number of cases = 3.

Thus, required probability = 3/6 = 1/2

(ii) A multiple of 3 is obtained if you obtain any one of 3, 6 as an outcome.

So, favourable number of cases = 2

Thus, required probability = 2/6 = 1/3

(iii) An even number or a multiple of 3 is obtained in any of the following outcomes 2, 3, 4, 6.

So, favourable number of cases = 4.

Thus, required probability = 4/6 = 2/3

(iv) An even number and a multiple of 3 is obtained if you get 6 as an outcome.

So, favourable number of cases = 1.

Thus, required probability = 1/6

Answer 2

Let the sample space of dice be 'P'

p = { 1, 2, 3, 4, 5, 6 }

n(S) = {6}

let the sample space of getting an even no. be 'A'

p = { 2, 4, 6 }

n(A) = {3}

The probability is -

p = n(A)

n(S)

= 3

6

°p = 1

2

pls confirm the second probability which u want