Question

An unbiased die is thrown. What is the probability of getting an even number a multiple of 3



a.A multiple of 2 or 3



b.A number less than 5 divisible by 2.



c.A number greater than 2 divisible by 3.



d.An even number or a multiple of 3



e.An even number and a multiple of 3 f) a number 3 or 4 g) an odd number h) a number less than i) a number greater than 3 j) a number between 3 and 6.

Answer 1

Answer:

Step-by-step explanation:

S=(1,2,3,4,5,6)

n(S)=6

EventA:Probablity of getting an even no. Multiple of 3

A=(6)

n(A)=1

P(A)=n (A)/n (S)

=1/6

EventB: multiple of 2 or 3

B=(2,3,4,6)

n (B)=4

P (B)=n (B)/n (S)

=4/6

=2/3

EventC:number less than 5 divisible by 2

C=(2,4)

n (C)=2

P (C)=n (C)/n (S)

=2/6

=1/3

EventD:number greater than 2 divisible by 3

D=(3,6)

n (D)=2

P (D)=n (D)/n (S)

=2/6

=1/3

EventE:even number or multiple of 3

E=(2,3,4,6)

n (E)=4

P (E)=n (E)/n (S)

=4/6

=2/3

EventF:a number 3 or 4

F=(3,4)

n (F)=2

P(F)=n (F)/n (S)

=2/6

=1/3

Event G:odd no.

G=(1,3,5)

n (G)=3

P (G)=n (G)/n (S)

=3/6

=1/2