an unbiased die is tossed find the probability of getting of multiple of 3
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Answered by
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Hey !!!!!!!
Total Outcomes (n) = 6
Favorable Outcomes (m) = 2 ( 3,6 )
P(getting a multiple of 3)
=m/n
=2/6
=1/3
Hope it helps
Total Outcomes (n) = 6
Favorable Outcomes (m) = 2 ( 3,6 )
P(getting a multiple of 3)
=m/n
=2/6
=1/3
Hope it helps
Answered by
1
probability of getting of multiple of 3 = 2/6 = 1/3
I hope it will help you
I hope it will help you
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