An unbiased die is tossed to until a number greater than 4 appears . The probability of even number of tosses
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Step-by-step explanation:
We have P(S)=P(5,6)=26
=13
=> P(F)=23
P (an even number of tosses is needed)
=P(FS or FFFS or FFFFFS or)
=> P(F)P(S)+P(F)3P(S)+P(F)6P(S)+
G.P with T1=P(F)P(S) and Common ratio P(F2))
=> P(E)P(S)1−P(F)2
=> 2/91−4/9=25
Answer : 25
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