Question

An unbiased die is tossed to until a number greater than 4 appears . The probability of even number of tosses

Answer 1

Answer:

Step-by-step explanation:

We have P(S)=P(5,6)=26

=13

=> P(F)=23

P (an even number of tosses is needed)

=P(FS or FFFS or FFFFFS or)

=> P(F)P(S)+P(F)3P(S)+P(F)6P(S)+

G.P with T1=P(F)P(S) and Common ratio P(F2))

=> P(E)P(S)1−P(F)2

=> 2/91−4/9=25

Answer : 25