An unbiased die is tossed twice find the probability of getting 4,5 or 6 on the first toss and 1,2,3 or 4 on the second toss
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The probability of getting 4,5 or 6 on the first toss and 1,2,3 or 4 on the second toss will be 1/3
Step-by-step explanation:
Since there are total 6 outcomes,
The probability of getting 4,5 or 6 on the first toss = 3/6 = 1/2
The probability of getting 1,2,3 or 4 on the second toss = 4/6 = 2/3
Since the events are independent so we multiply the individual probabilities to get the overall probability,
Hence net probability = 1/2 x 2/3 = 1/3
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