Question

An uncharged particle is moving with a velocity of y
in nonuniform magnetic field as shwon. [AIIMS-2010)
velocity v would be:
M
A
B
(1) maximum at A and B (2) minimum at A and B
(3) maximum at M (4) same at all points​

Answer 1

Explanation:

ANSWER

Magnetic force is given as F=qvBsinθ it is given that angle between field B and velocity v is 90

0

and q=1.6×10

−19

C so we get the value of force as F=1.6×10

−16

N so m=1 is the required answer.

HOPE IT HELPS....!

Answer 2

Answer:

if particle is uncharged then magnetic field would not effect its velocity so its velocity Will remain same.

still you must use camera option of brainly app to upload diagram of your question as well so that it can be answered in a better way