Question

an undergoes an acceleration of 8 m/s^2 starting from rest. Find distance travelled in 1 s

Answer 1

Answer:

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Explanation:

Initial velocity = 0 m/s,

Acceleration = 8m/s ²,

time taken = 1 sec,

And we have to find distance ,

so distance will be,

S = ut+ ½at ²,

S = 0 * 1 + ½ *8*1*1,

S = 4 * 1,

S = 4,

Therefore distance traveled = 4 m.

I hope it helps…………….✔✔✔

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Answer 2

u = 0 , t= 1 sec ,a= 8 m per sec sq v=

now , a = v plus u by t = v+ 0 / 1 = 8

v = 8 m per sec

now s = ut plus half at sq

distance = o x 1 + 1/ 2 × 8 × 1 =

= 0 + 4 = 4 m

hope it is beneficial for u